The base angle of an isosceles triangle measures 54°. What is the measure of its vertex angle?

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OmarWalid OmarWalid · Answer 1 · 2016-12-03T20:38:39+01:00

We know that in an isosceles triangle the two base angles are equal so let's get the sum of both
54+54 = 108
So the vertex angle equals
180-108
72°

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Cricetus Cricetus · Answer 2 · 2019-07-03T07:43:32+02:00

Answer:

72[tex]\degree[/tex]

Step-by-step explanation:

We know that the sum of all the angles of any triangle is 180[tex]\degree[/tex]

We have to use the above property in order to find the measurement of the vertex angle.

Now our triangle is isosceles , that is the two equal sides will be containing equal angle. One of them is given as 54[tex]\degree[/tex]

And hence the other will also be 54[tex]\degree[/tex].

Let the vertex angle be x

180=54+54+×

180=108+×

x=180-108

x=72

Hence the vertex angle is 72[tex]\degree[/tex]