Chris has twice as many $1 bills as
pennies. He has twice as many dimes as
he has $10 bills. He has twice as many
pennies as he has dimes. How much
money does Chris have?
There is not enough information to give a numerical answer. Let t=number of ten dollar bills. "he has twice as many dimes as he has 10 dollar bills", so the amount A is A=10*t+0.1*(2t) "he has twice as many pennies as he has dimes" A=10*t+0.1*(2t)+0.01*4t "chris has twice as many 1 dollar bills as pennies" A=10*(t)+0.1*(2t)+0.01*(4t)+1*(8t) =18.24t Therefore the total amount Chris has is 18.24 times the number of $10 bills he possesses.
