Respuesta :

m(Ag)=12.5 g
Nₐ=6.022*10²³ mol⁻¹

n(Ag)=m(Ag)/M(Ag)

N=n(Ag)*Nₐ

N=Nₐm(Ag)/M(Ag)

N=6.022*10²³mol⁻¹*12.5g/107.868g/mol=6.97*10²²


A. 6.97 × 10²² atoms

Given,

Mass of silver (Ag) = 12.5 g

Nₐ=6.022*10²³ mol⁻¹

What is atom?

Atom is smallest unit into which matter can be divided without the release of electrically charged particles.

n(Ag)=m(Ag)/M(Ag)

N=n(Ag)*Nₐ

N=Nₐm(Ag)/M(Ag)

N=6.022*10²³mol⁻¹*12.5g/107.868g/mol=6.97*10²²

Thus the 12.5 grams of silver have 6.97 × 10²² atoms.

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