Respuesta :

sbcardinals
If we take the equation and multiply out the left side, we get....

[tex] x^{2} [/tex] + 2xk + [tex] k^{2} [/tex] = [tex] x^{2} [/tex] + x +[tex] k^{2} [/tex]

The x^2 and k^2 cancel out on both sides leaving us with this...

2kx = x

If we divide both sides by 2x to isolate k, k ends up = 1/2

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